LTM4600
APPLICATIONS INFORMATION
t
ON
(DC) DUTY CYCLE =
t
t
= 0.41 • 1μs ≅ 410ns
ON
t
s
t
V
OUT
ON
DC =
=
t
s
V
IN
= 1μs – 410ns ≅ 590ns
OFF
DC
FREQ =
t
ON
t
t
ON
OFF
t
and t are above the minimums with adequate guard
OFF
ON
band.
4600 F21
PERIOD t
s
Using the frequency = (I /[2.4V • 10pF]) • DC, solve for
ON
I
= (1MHz • 2.4V • 10pF) • (1/0.41) ≅ 58μA. I current
ON
ON
Figure 17. LTM4600 Switching Period
calculated from 12V input was 103μA, so a resistor from
f
to ground = (0.7V/15k) = 46μA. 103μA – 46μA =
TheLTM4600hasaminimum(t )ontimeof100nanosec-
ADJ
ON
57μA, sets the adequate I current for proper frequency
onds and a minimum (t ) off time of 400 nanoseconds.
ON
OFF
range for the higher duty cycle conversion of 12V to
The 2.4V clamp on the ramp threshold as a function of
5V. Input voltage range is limited to 9V to 16V. Higher
V
will cause the switching frequency to increase by the
OUT
input voltages can be used without the 15k on f . The
ratio of V /2.4V for 3.3V and 5V outputs. This is due to
ADJ
OUT
inductor ripple current gets too high above 16V, and the
the fact the on time will not increase as V
increases
OUT
400ns minimum off-time is limited below 9V.
past 2.4V. Therefore, if the nominal switching frequency
is 850kHz, then the switching frequency will increase
to ~1.2MHz for 3.3V, and ~1.7MHz for 5V outputs due
Equations for setting frequency for 5V to 3.3V:
I
ON
= (V – 0.7V)/110k; I = 39μA
IN ON
to Frequency = (DC/t ) When the switching frequency
ON
increases to 1.2MHz, then the time period t is reduced
S
frequency = (I /[2.4V • 10pF]) • DC = 1.07MHz;
ON
to ~833 nanoseconds and at 1.7MHz the switching period
reduces to ~588 nanoseconds. When higher duty cycle
conversions like 5V to 3.3V and 12V to 5V need to be
accommodated, then the switching frequency can be
lowered to alleviate the violation of the 400ns minimum
DC = duty cycle, duty cycle is (V /V )
OUT IN
t = t + t , t = DC • t , t = off-time of the
OFF
S
ON
OFF ON
S
switching period; t = 1/frequency
S
t
must be greater than 400ns, or t – t > 400ns.
S ON
OFF
off time. Since the total switching period is t = t + t
,
S
ON OFF
The ~450kHz frequency or 2.22μs period is chosen for
5V to 3.3V. Frequency range is about 450kHz to 650kHz
from 4.5V to 7V input.
t
will be below the 400ns minimum off time. A resistor
OFF
from the f
pin to ground can shunt current away from
ADJ
the on time generator, thus allowing for a longer on time
and a lower switching frequency. 12V to 5V and 5V to
3.3V derivations are explained in the data sheet to lower
switching frequency and accommodate these step-down
conversions.
t
t
= 0.66 • 2.22μs ≅ 1.46μs
= 2.22μs – 1.46μs ≅ 760ns
ON
OFF
t
and t are above the minimums with adequate guard
OFF
ON
band.
Equations for setting frequency for 12V to 5V:
Using the frequency = (I /[2.4V • 10pF]) • DC, solve for
ON
I
ON
= (V – 0.7V)/110k; I = 103μA
IN ON
I
ON
= (450kHz • 2.4V • 10pF) • (1/0.66) ≅ 16μA. I current
ON
calculated from 5V input was 39μA, so a resistor from f
frequency = (I /[2.4V • 10pF]) • DC = 1.79MHz;
ADJ
ON
to ground = (0.7V/30.1k) = 23μA. 39μA – 23μA = 16μA,
DC = duty cycle, duty cycle is (V /V )
OUT IN
sets the adequate I current for proper frequency range
ON
t = t + t , t = on-time, t = off-time of the
OFF
S
ON
OFF ON
for the higher duty cycle conversion of 5V to 3.3V. Input
switching period; t = 1/frequency
S
voltagerangeislimitedto4.5Vto7V.Higherinputvoltages
t
must be greater than 400ns, or t – t > 400ns.
S ON
can be used without the 30.1k on f . The inductor ripple
OFF
ADJ
current gets too high above 7V, and the 400ns minimum
t
= DC • t
S
ON
off-time is limited below 4.5V.
1MHz frequency or 1μs period is chosen for 12V to 5V.
4600fc
17