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NX2142CUTR

型号:

NX2142CUTR

描述:

与前馈和5V偏置稳压器单通道PWM控制器[ SINGLE CHANNEL PWM CONTROLLER WITH FEEDFORWARD AND 5V BIAS REGULATOR ]

品牌:

MICROSEMI[ Microsemi ]

页数:

18 页

PDF大小:

525 K

NX2142/2142A  
SINGLE CHANNEL PWM CONTROLLER WITH FEEDFORWARD  
AND 5V BIAS REGULATOR  
ADVANCE DATA SHEET  
Pb Free Product  
FEATURES  
DESCRIPTION  
n
n
n
Bus voltage operation from 7V to 24V  
5V bias regulator available  
The NX2142/2142A controller IC is a compact synchro-  
nous Buck controller IC with 10 lead MSOP package  
designed for step down DC to DC converter applica-  
tions with voltage feedforward functionality. Voltage  
feedforward provides fast response, good line regula-  
tion and nearly constant power stage gain under wide  
voltage input range. The NX2142/2142A controller is  
optimized to convert single supply up to 24V bus volt-  
age to as low as 0.8V output voltage. NX2142/2142A  
can function as a single supply controller with its 5V  
bias regulator. Internal UVLO keeps the regulator off  
until the supply voltage exceeds 7V where internal digi-  
tal soft starts get initiated to ramp up output. The  
NX2142/2142A employs fixed current limiting and FB  
UVLO followed by hiccup feature. Other features in-  
cludes: 5V gate drive capability , Converter Shutdown  
by pulling COMP pin to Gnd, Adaptive dead band con-  
trol.  
Excellent dynamic response with input voltage  
feed-forward and voltage mode control  
Fixed 600kHz, 1MHz switching frequency  
Internal Digital Soft Start Function  
Fixed internal hiccup current limit  
FB UVLO followed by hiccup feature  
Shutdown by pulling COMP pin low  
Pb-free and RoHS compliant  
n
n
n
n
n
n
APPLICATIONS  
Graphic Card on board converters  
Vddq Supply in mother board applications  
On board DC to DC such as  
n
n
n
12V to 3.3V, 2.5V or 1.8V  
Set Top Box and LCD Display  
n
TYPICAL APPLICATION  
Vin  
+8 to 20V  
25TQC33M  
47uF  
1uF  
MMBT3904  
BAT54A  
1uF  
1
7
0.1uF  
BST  
Hdrv  
VCC  
REGOUT  
6
2
AO4800(half)  
DO3316P-682  
5
VIN  
0.1uF  
20k  
Vout  
10  
4
9
8
SW  
COMP  
+3.3V /3A  
1000uF,30mohm  
27pF  
AO4800(half)  
Ldrv  
5.2nF  
1k  
FB  
Gnd  
3
324  
Figure1 - Typical application of NX2142  
ORDERING INFORMATION  
Device  
NX2142CUTR  
NX2142ACUTR  
Temperature  
0 to 70o C  
0 to 70o C  
Package  
MSOP-10L  
MSOP-10L  
Frequency  
600kHz  
1MHz  
Pb-Free  
Yes  
Yes  
Rev. 1.1  
10/28/07  
1
NX2142/2142A  
ABSOLUTE MAXIMUM RATINGS  
VCC to GND & BST to SW voltage ...................... -0.3V to 6.5V  
VIN to GND ........................................................ -0.3V to 30V  
BST to GND Voltage .......................................... -0.3V to 35V  
SW to GND ....................................................... -2V to 35V  
REGOUT to GND ................................................ 0.2 to 16V  
All other pins ..................................................... -0.3V to 6.5V  
Storage Temperature Range ................................ -65oC to 150oC  
Operating Junction Temperature Range ................ -40oC to 125oC  
ESD Susceptibility ............................................ 2kV  
CAUTION: Stresses above those listed in "ABSOLUTE MAXIMUM RATINGS", may cause permanent  
damage to the device. This is a stress only rating and operation of the device at these or any other conditions  
above those indicated in the operational sections of this specification is not implied.  
PACKAGE INFORMATION  
10-LEAD PLASTIC MSOP  
qJA » 200oC/W  
BST  
1
10  
9
SW  
COMP  
HDrv 2  
GND  
LDrv  
VIN  
8
3
4
5
FB  
7 VCC  
REGOUT  
6
ELECTRICAL SPECIFICATIONS  
Unless otherwise specified, these specifications apply over Vcc =5V, VIN=15V and TA = 0 to 70oC. Typical  
values refer to TA = 25oC.  
PARAMETER  
Reference Voltage  
Ref Voltage  
SYM  
Test Condition  
Min  
TYP  
MAX Units  
VREF  
0.8  
0.2  
V
Ref Voltage line regulation  
Supply Voltage(Vcc)  
VCC Voltage Range  
Operating quiescent current  
Vcc UVLO  
%
VCC  
IQ  
5
3
V
EN=HIGH  
mA  
VCC-Threshold  
VCC_UVLO VCC Rising  
VCC_Hyst VCC Falling  
4.4  
0.2  
V
V
VCC-Hysteresis  
Supply Voltage(Vin)  
Vin Voltage Range  
Input Voltage Current  
Vin UVLO  
Vin  
V
7
25  
Vin=24V  
9
6
mA  
Vin-Threshold  
Vin_UVLO Vin Rising  
V
Rev. 1.1  
10/28/07  
2
NX2142/2142A  
PARAMETER  
Vin-Hysteresis  
SYM  
Test Condition  
Min  
TYP  
0.5  
MAX Units  
Vin_Hyst Vin Falling  
V
Oscillator (Rt)  
Frequency  
FS  
NX2142  
600  
1000  
1
KHz  
KHz  
%
NX2142A  
Frequency Over Vin  
Ramp Peak to Peak Voltage  
Ramp Valley Voltage  
Ramp Peak to Peak/Vin Gain  
Max Duty Cycle  
VRAMP  
Vin=20V  
2
V
0.8  
0.1  
77  
0
V
V/V  
%
FS=600kHz  
Min Duty Cycle  
%
Min Controllable on time  
Error Amplifiers  
nS  
150  
100  
Transconductance  
Input Bias Current  
Comp SD threshold  
Soft Start  
2500  
0.3  
umho  
nA  
Ib  
V
Soft Start time  
Tss  
NX2142  
3.4  
2
mS  
mS  
NX2142A  
High Side Driver  
(CL=3300pF)  
Output Impedance , Sourcing Rsource(Hdrv)  
Current  
I=200mA  
1
ohm  
ohm  
Output Impedance , Sinking  
Current  
Rsink(Hdrv)  
I=200mA  
0.8  
Rise Time  
THdrv(Rise)  
THdrv(Fall)  
10% to 90%  
90% to 10%  
50  
50  
30  
ns  
ns  
ns  
Fall Time  
Deadband Time  
Tdead(L to Ldrv going Low to Hdrv going  
H)  
High, 10% to 10%  
LowNSide Driver  
(CL=3300pF)  
Output Impedance, Sourcing Rsource(Ldrv)  
Current  
I=200mA  
I=200mA  
1
ohm  
ohm  
Output Impedance, Sinking  
Current  
Rsink(Ldrv)  
0.5  
Rise Time  
TLdrv(Rise)  
TLdrv(Fall)  
10% to 90%  
90% to 10%  
50  
50  
30  
ns  
ns  
ns  
Fall Time  
Deadband Time  
Tdead(H to SW going Low to Ldrv going  
L) High, 10% to 10%  
Fixed OCP  
OCP voltage threshold  
FBUVLO  
320  
70  
mV  
%
Feedback UVLO threshold  
percent of nominal  
Over temperature  
Threshold  
150  
20  
°C  
°C  
Hysteresis  
Rev. 1.1  
10/28/07  
3
NX2142/2142A  
PIN DESCRIPTIONS  
PIN SYMBOL  
PIN DESCRIPTION  
This pin supplies the internal 5V bias circuit. A 1uF high frequency ceramic X5R  
capacitor must be placed as close as possible to this pin and ground pin to provide  
high frequency bypass and to make the 5V regulator stable.  
VCC  
This pin supplies voltage to high side FET driver. A minimum 0.1uF ceramic high  
frequency capacitor is placed as close as possible to and connected to this pin and  
SW pin.  
BST  
GND  
FB  
Power ground.  
This pin is the error amplifiers inverting input. It is connected via resistor divider to  
the output of the switching regulator to set the output DC voltage.  
This pin is the output of the error amplifier and together with FB pin is used to compen-  
sate the voltage control feedback loop. You can shutdown the switching regulator by  
pulling this pin below 0.3V.  
COMP  
SW  
This pin is connected to source of high side FETs and provides return path for the  
high side driver. This pin also provides input for the OCP comparator by sensing the  
RDSON of the lower MOSFET. When this pin is below ground by 320mV, both drivers  
are shutdown and enter hiccup mode.  
High side gate driver output.  
Low side gate driver output.  
HDRV  
LDRV  
The output of the 5V regulator controller that drives a low current low cost external  
bipolar transistor or an external MOSFET to regulate the voltage at Vcc pin derived  
from bus voltage. This eliminates an otherwise external regulator needed in applica-  
tions where 5V is not available. This regulator request a 1uF ceramic X5R type output  
REGOUT  
capacitor in order to be stable.  
This pin provides the input voltage to the 5V regulator controller as well as the  
oscillator for the PWM feed forward to work. When VIN exceeds 6V, the converter  
starts to operate.  
VIN  
Rev. 1.1  
10/28/07  
4
NX2142/2142A  
BLOCK DIAGRAM  
VIN  
Ref  
Regout  
4.4/4.2V  
1.25V  
0.8V  
Bias  
Generator  
VCC  
BST  
POR  
OC  
UVLO  
START  
HDRV  
SW  
6V/  
5.5V  
COMP  
0.3V  
VIN  
Control  
Logic  
0.8V  
START  
OSC  
ramp  
PWM  
OC  
VCC  
Digital  
start Up  
S
R
LDRV  
Q
FB  
POR  
0.6V  
CLAMP  
1.3V  
CLAMP  
320mV  
COMP  
Hiccup Logic  
START  
OCP  
comparator  
SS_half_done  
70%*Vp  
FB  
GND  
Figure 2 - Simplified block diagram of the NX2142  
Rev. 1.1  
10/28/07  
5
NX2142/2142A  
TYPICAL APPLICATION CIRCUIT  
BUS  
BUS(8-20V)  
C10  
47u  
GNDBUS  
C6  
0.1u  
C2  
1u  
D1  
BAT54A  
Ci1  
Q1  
2N3904  
25TQC33M  
C14  
U1  
BST  
1
BST  
1u  
C1  
0.1u  
M5A  
STM6912  
EN_REGOUT  
U_HDRV  
HDRV  
6
2
2
EN/REG_OUT  
HDRV  
SW  
VOUT  
Lo  
DO3316P-682  
U_SW  
SW  
OUT(5V)  
10  
1
2
Co1  
1000uF, 6.3v,30mohm  
GNDOUT  
R15  
10  
M6B  
STM6912  
U_LDRV  
LDRV  
4
4
LDRV  
C9  
470p  
C5  
R8  
FB  
8
9
FB  
1.2k  
25n  
R7  
R10  
953  
R9  
4.99k  
10k  
C4  
52p  
C3  
3.3n  
COMP  
COMP  
Figure 3- Demo board schematic(VIN=8-20V,VOUT=5V,IOUT=3A)  
Rev. 1.1  
10/28/07  
6
NX2142/2142A  
Bill of Materials  
Item  
1
2
3
4
5
6
7
8
Quantity  
Reference  
Value  
25TQC33M  
6MV1000WG  
0.1u  
1u  
3.3n  
52p  
25n  
470p  
47u  
BAT54A  
DO3316P-682  
AO4800  
MMBT3904  
10k  
Manufacture  
SANYO  
SANYO  
1
1
2
3
1
1
1
1
1
1
1
2
1
1
1
1
1
1
1
Ci1  
Co1  
C1,C6  
C2,C14  
C3  
C4  
C5  
C9  
C10  
D1  
Lo  
M5,M6  
Q1  
R7  
R8  
R9  
R10  
R15  
U1  
9
10  
11  
12  
13  
14  
15  
16  
17  
18  
19  
Fairchild  
Coilcraft  
AOS  
Fairchild  
1.2k  
4.99k 1%  
953 1%  
10  
NX2142CUTR  
NEXSEM INC.  
Rev. 1.1  
10/28/07  
7
NX2142/2142A  
Demoboard waveforms  
Figure 5 - Output voltage transient response  
(VIN=12V, IOUT=3A)  
Figure 4 - Output ripple (VIN=12V)  
Figure 6 - Over current protection  
Figure 7 - Startup  
100.00%  
95.00%  
90.00%  
85.00%  
80.00%  
75.00%  
70.00%  
65.00%  
60.00%  
55.00%  
50.00%  
0
500  
1000  
1500  
2000  
2500  
3000  
3500  
Iout(mA)  
Figure 8 - Output Efficiency(VIN=12V, VOUT=5V)  
Rev. 1.1  
10/28/07  
8
NX2142/2142A  
Current Ripple is calculated as  
APPLICATION INFORMATION  
V -VOUT VOUT  
1
IN  
IRIPPLE  
=
´
´
LOUT  
V
F
IN  
S
Symbol Used In Application Information:  
...(2)  
20V-5V 5V  
1
=
´
´
= 0.919A  
VIN  
- Input voltage  
- Output voltage  
- Output current  
6.8uH 20V 600kHz  
VOUT  
IOUT  
Output Capacitor Selection  
VRIPPLE - Output voltage ripple  
Output capacitor is basically decided by the  
amount of the output voltage ripple allowed during  
steady state(DC) load condition as well as specifica-  
tion for the load transient. The optimum design may  
require a couple of iterations to satisfy both condition.  
Based on DC Load Condition  
FS  
- Switching frequency  
- Inductor current ripple  
IRIPPLE  
Design Example  
Power stage design requirements:  
VINMIN=8V  
The amount of voltage ripple during the DC load  
condition is determined by equation(3).  
VINMAX=20V  
VOUT=5V  
DIRIPPLE  
DVRIPPLE = ESR´ DIRIPPLE  
+
...(3)  
IOUT =3A  
8´ F ´ COUT  
S
VRIPPLE <=50mV  
VTRAN<=150mV @ 1.5A step  
FS=600kHz  
Where ESR is the output capacitors' equivalent  
series resistance,COUT is the value of output capaci-  
tors.  
Typically when large value capacitors are selected  
such as Aluminum Electrolytic,POSCAP and OSCON  
types are used, the amount of the output voltage ripple  
is dominated by the first term in equation(3) and the  
second term can be neglected.  
Output Inductor Selection  
The selection of inductor value is based on in-  
ductor ripple current, power rating, working frequency  
and efficiency. Larger inductor value normally means  
smaller ripple current. However if the inductance is  
chosen too large, it brings slow response and lower  
efficiency. Usually the ripple current ranges from 20%  
to 40% of the output current. This is a design freedom  
which can be decided by design engineer according to  
various application requirements. The inductor value  
can be calculated by using the following equations:  
For this example, Aluminum Electrolytic is cho-  
sen as output capacitor, the ESR and inductor current  
typically determines the output voltage ripple.  
DVRIPPLE  
DIRIPPLE  
50mV  
ESRdesire  
=
=
= 54mW  
...(4)  
0.919A  
If low ESR is required, for most applications, mul-  
tiple capacitors in parallel are better than a big capaci-  
tor. For example, for 50mV output ripple, Electrolytic  
6ME1000WG with 30mW are chosen.  
V
INMAX-V  
V
OUT  
1
OUT  
LOUT  
=
´
´
IRIPPLE  
IRIPPLE=k´ IOUTPUT  
V
F
S
INMAX  
...(1)  
E S R E ´ DIR IPPLE  
N =  
where k is between 0.2 to 0.4.  
Select k=0.3, then  
...(5)  
D VR IPPLE  
Number of Capacitor is calculated as  
20V-5V 5V  
1
LOUT  
=
´
´
30mW´ 0.919A  
N=  
0.3´ 3A 20V 600kHz  
LOUT =6.9uH  
50mV  
N =0.55  
Choose LOUT=6.8uH, then coilcraft inductor  
DO3316P-682HC is a good choice.  
The number of capacitor has to be round up to a  
integer. Choose N =1.  
Rev. 1.1  
10/28/07  
9
NX2142/2142A  
If ceramic capacitors are chosen as output ca-  
pacitors, both terms in equation (3) need to be evalu-  
ated to determine the overall ripple. Usually when this  
type of capacitors are selected, the amount of capaci-  
tance per single unit is not sufficient to meet the tran-  
sient specification, which results in parallel configura-  
tion of multiple capacitors.  
tance of each capacitor if multiple capacitors are used  
in parallel.  
The above equation shows that if the selected  
output inductor is smaller than the critical inductance,  
the voltage droop or overshoot is only dependent on  
the ESR of output capacitor. For low frequency ca-  
pacitor such as electrolytic capacitor, the product of  
For example, one 100uF, X5R ceramic capaci-  
ESR and capacitance is high and L £ Lcrit is true. In  
that case, the transient spec is mostly like to depen-  
dent on the ESR of capacitor.  
tor with 2mW ESR is used. The amount of output ripple  
is  
0.919A  
Most case, the output capacitor is multiple ca-  
pacitor in parallel. The number of capacitor can be cal-  
culated by the following  
DV  
= 2mW´ 0.919A +  
RIPPLE  
8´ 600kHz´ 100uF  
=1.838mV+1.9mV = 3.738mV  
One ceramic capacitors are needed. Although  
this can meet DC ripple spec, however it needs to be  
ESRE ´ DIstep  
VOUT  
N =  
where  
+
´ t 2  
...(9)  
DV  
2´ L´ CE ´ DV  
tran  
tran  
studied for transient requirement.  
Based On Transient Requirement  
Typically, the output voltage droop during tran-  
sient is specified as  
0
if L £ Lcrit  
ì
ï
L´ DI  
t =  
í
ï
î
step  
...(10)  
- ESRE ´ CE  
if L ³ Lcrit  
VOUT  
DV  
< DV  
@step load I  
tran  
droop  
STEP  
During the transient, the voltage droop during  
the transient is composed of two sections. One sec-  
tion is dependent on the ESR of capacitor, the other  
section is  
For example, assume voltage droop during tran-  
sient is 150mV for 1.5A load step.  
If the Electrolytic 6ME1000WG(1000uF, 30mohm  
ESR) is used, the crticial inductance is given as  
a function of the inductor, output capacitance as well  
as input, output voltage. For example, for the  
overshoot when load from high load to light load  
with a ISTEP transient load, if assuming the band-  
width of system is high enough, the overshoot can  
be estimated as the following equation.  
ESRE ´ CE ´ VOUT  
Lcrit  
=
=
DIstep  
30m1000mF´ 5V  
=100mH  
1.5A  
The selected inductor is 6.8uH which is much  
smaller than critical inductance. In that case, the out-  
put voltage transient not only dependent on the ESR,  
but also capacitance.  
VOUT  
DVovershoot = ESR ´ DIstep  
+
´ t 2  
...(6)  
2´ L´ COUT  
where  
is the a function of capacitor,etc.  
t
number of capacitor is  
0
if L £ Lcrit  
ì
ï
ESRE ´ DIstep  
N =  
t = L´ DI  
í
step  
...(7)  
...(8)  
- ESR ´ COUT  
if L ³ Lcrit  
ï
DV  
tran  
VOUT  
î
30m1.5A  
where  
ESR ´ COUT ´ VOUT ESRE ´ CE ´ VOUT  
=
200mV  
= 0.225  
Lcrit  
=
=
DIstep  
DIstep  
where ESRE and CE represents ESR and capaci-  
The number of capacitors has to satisfy both ripple  
and transient requirement. Overall, we choose N=1.  
Rev. 1.1  
10/28/07  
10  
NX2142/2142A  
It should be considered that the proposed equa- following figures and equations show how to realize  
tion is based on ideal case, in reality, the droop or over- the type III compensator by transconductance ampli-  
shoot is typically more than the calculation. The equa- fier.  
tion gives a good start. For more margin, more ca-  
1
pacitors have to be chosen after the test. Typically, for  
high frequency capacitor such as high quality POSCAP  
especially ceramic capacitor, 20% to 100% (for ce-  
ramic) more capacitors have to be chosen since the  
ESR of capacitors is so low that the PCB parasitic can  
affect the results tremendously. More capacitors have  
to be selected to compensate these parasitic param-  
eters.  
FZ1  
FZ2  
=
=
=
=
...(11)  
...(12)  
...(13)  
...(14)  
2´ p ´ R4 ´ C2  
1
2´ p ´ (R2 + R3 )´ C3  
1
F
P1  
2´ p ´ R3 ´ C3  
1
F
P2  
C1 ´ C2  
2´ p ´ R4 ´  
C1 + C2  
Compensator Design  
where FZ1,FZ2,FP1 and FP2 are poles and zeros in  
the compensator.  
Due to the double pole generated by LC filter of  
the power stage, the power system has 180o phase  
shift , and therefore, is unstable by itself. In order to  
achieve accurate output voltage and fast transient re-  
sponse, compensator is employed to provide highest  
possible bandwidth and enough phase margin. Ideally,  
the Bode plot of the closed loop system has crossover  
frequency between 1/10 and 1/5 of the switching fre-  
quency, phase margin greater than 50o and the gain  
crossing 0dB with -20dB/decade. Power stage output  
capacitors usually decide the compensator type. If  
electrolytic capacitors are chosen as output capacitors,  
type II compensator can be used to compensate the  
system, because the zero caused by output capacitor  
ESR is lower than crossover frequency. Otherwise type  
III compensator should be chosen.  
The transfer function of type III compensator for  
transconductance amplifier is given by:  
Ve  
1- gm ´ Zf  
=
VOUT  
1+ gm ´ Zin + Zin /R1  
For the voltage amplifier, the transfer function of  
compensator is  
Ve  
- Zf  
=
VOUT  
Zin  
To achieve the same effect as voltage amplifier,  
the compensator of transconductance amplifier must  
satisfy this condition: R4>>2/gm. And it would be de-  
sirable if R1||R2||R3>>1/gm can be met at the same  
time,  
Voltage feedforward compensation is used in  
NX2142 to compensate the output voltage variation  
caused by input voltage changing. The feedforward  
funtion is realized by using VIN pin voltage to program  
the oscillator ramp voltage VOSC at about 1/10 of VIN  
voltage, which provides nearly constant power stage  
gain under wide voltage input range.  
Zf  
Vout  
Zin  
C1  
R3  
C2  
R4  
R2  
R1  
C3  
Fb  
Ve  
gm  
A. Type III compensator design  
For low ESR output capacitors, typically such as  
Sanyo oscap and poscap, the frequency of ESR zero  
caused by output capacitors is higher than the cross-  
over frequency. In this case, it is necessary to com-  
pensate the system with type III compensator. The  
Vref  
Figure 9 - Type III compensator using  
transconductance amplifier  
Rev. 1.1  
10/28/07  
11  
NX2142/2142A  
Case 1:  
FLC<FO<FESR(for most ceramic or low  
2. Set R4 equal to 10kW.  
ESR POSCAP, OSCON)  
3. Calculate C2 with zero Fz1 at 50% of the LC  
double pole by equation (11).  
1
power stage  
C2 =  
2 ´ p ´ FZ1 ´ R4  
LC  
F
1
=
40dB/decade  
2 ´ p ´ 0.5 ´ 9.2kHz ´ 10kW  
= 3.5nF  
Choose C2=3.9nF.  
4. Calculate C1 by equation (14) with pole Fp2 at  
half the switching frequency.  
loop gain  
ESR  
F
1
C1 =  
20dB/decade  
2 ´ p ´ R4 ´ FP2  
1
=
compensator  
2 ´ p ´ 10k300kHz  
= 53pF  
Choose C1=52pF.  
5. Calculate C3 with the crossover frequency at  
1/10~ 1/5 of the switching frequency. Set FO=60kHz.  
FZ1  
FO  
FP2  
FZ2  
F
P1  
VOSC 2´ p ´ FO ´ L  
C3 =  
´
´ Cout  
V
R4  
in  
Figure 10 - Bode plot of Type III compensator  
(FLC<FO<FESR  
1
2´ p ´ 60kHz ´ 6.8uH  
10kW  
)
=
´
´ 44uF  
10  
=1.1nF  
Typical design example of type III compensator  
in which the crossover frequency is selected as  
FLC<FO<FESR and FO<=1/10~1/5Fs is shown as the  
following steps. Here two X5R 22uF ceramic capacitor  
with3mW is chosen as output capacitor, output inductor  
is 6.8uH.  
Choose C3=1.2nF.  
6. Set zero FZ2 = 0.75FLC and Fp1 =0.5Fs, calcu-  
late R2.  
1
1
1
R2=  
´ (  
-
)
1. Calculate the location of LC double pole FLC  
2´ p´ C3  
F
F
p1  
z2  
and ESR zero FESR  
.
1
1
1
=
´ (  
-
)
2´ p´ 1.2nF 0.75*9.2kHz 300kHz  
=18kW  
1
F
=
=
LC  
2´ p ´ LOUT ´ COUT  
1
Choose R2=20kW.  
7. Calculate R3 by equation (13) with Fp1 =Fs.  
2 ´ p ´ 6.8uH´ 44uF  
= 9.2kHz  
1
R3 =  
2´ p ´ F ´ C3  
P1  
1
1
FESR  
=
=
2 ´ p ´ ESR ´ COUT  
1
2´ p ´ 600kHz´ 1.2nF  
= 221W  
=
2´ p ´ 1.5m44uF  
Choose R3 =300W.  
= 241kHz  
Rev. 1.1  
10/28/07  
12  
NX2142/2142A  
8. Calculate R1.  
1
F
=
=
ESR  
R2 ´ VREF  
R1=  
20k0.8V  
2´ p ´ ESR´ COUT  
=
= 5.7kW  
VOUT -VREF  
5V-0.8V  
1
2´ p ´ 30m1000uF  
Choose R1=5.7kW.  
= 5.3kHz  
2. Set R4 equal to 10kW.  
Case 2:  
FLC<FESR<FO(for electrolytic capacitors)  
3. Calculate C2 with zero Fz1 at 75% of the LC  
double pole by equation (11).  
power stage  
LC  
F
1
C2 =  
2´ p ´ FZ1 ´ R4  
40dB/decade  
1
=
2´ p ´ 0.75 ´ 1.93kHz ´ 10kW  
= 10nF  
ESR  
F
loop gain  
Choose C2=10nF.  
4. Calculate C1 by equation (14) with pole Fp2 at  
half the switching frequency.  
20dB/decade  
1
C1 =  
2 ´ p ´ R4 ´ FP2  
compensator  
1
=
2 ´ p ´ 10k300kHz  
= 53pF  
Choose C1=52pF.  
FZ1  
FO  
FP2  
FZ2  
F
P1  
5. Calculate C3 with the crossover frequency at  
1/10~ 1/5 of the switching frequency. Set FO=60kHz.  
Figure 11 - Bode plot of Type III compensator  
(FLC<FESR<FO)  
VOSC  
Vin  
FO ´ L  
C 3 =  
=
´
ESR ´ R 4 ´ FP 1  
60kHz ´ 6.8uH  
If electrolytic capacitors are used as output  
capacitors, typical design example of type III  
compensator in which the crossover frequency is  
selected as FLC<FESR<FO and FO<=1/10~1/5Fs is shown  
as the following steps. Here one SANYO 6ME-WG1000  
with 30 mW is chosen as output capacitor, output  
inductor is 6.8uH.  
1
´
10 30m W ´ 10kW ´ 5.3kHz  
=25nF  
Choose C3=25nF.  
6. Set zero FZ2 = FLC and Fp1 =FESR, calculate R2.  
1
1
1
R2 =  
´ (  
-
)
1. Calculate the location of LC double pole FLC  
2´ p ´ C3  
Fz2 F  
p1  
and ESR zero FESR  
.
1
1
1
=
´ (  
-
)
2´ p ´ 25nF 1.93kHz 5.3kHz  
1
F
=
=2kW  
Choose R2=20kW.  
7. Calculate R3 by equation (13) with Fp1 =FESR  
LC  
2´ p ´  
L
OUT ´ COUT  
1
=
.
2´ p ´ 6.8uH´ 1000uF  
= 1.93kHz  
Rev. 1.1  
10/28/07  
13  
NX2142/2142A  
1
R3 =  
2´ p ´ F ´ C3  
P1  
power stage  
1
=
2´ p ´ 5.3kHz´ 25nF  
= 1.2kW  
40dB/decade  
Choose R3 =1.2kW.  
8. Calculate R1.  
loop gain  
R2 ´ VREF  
1.2k0.8V  
R1=  
=
= 381W  
VOUT -VREF  
5V-0.8V  
20dB/decade  
Choose R1=381W.  
B. Type II compensator design  
compensator  
If the electrolytic capacitors are chosen as  
power stage output capacitors, usually the Type II  
compensator can be used to compensate the sys-  
tem.  
Gain  
P
F
F
F
Z
LCFESR  
FO  
For this type of compensator, FO has to satisfy  
FLC<FESR<<FO<=1/10~1/5Fs.  
Figure 12 - Bode plot of Type II compensator  
Case 1:  
C2  
Type II compensator can be realized by simple  
RC circuit as shown in figure 13. R3 and C1 introduce a  
zero to cancel the double pole effect. C2 introduces a  
Vout  
C1  
R3  
R2  
pole to suppress the switching noise.  
To achieve the same effect as voltage amplifier,  
the compensator of transconductance amplifier must  
Fb  
Ve  
gm  
R1  
satisfy this condition: R3>>1/gm and R1||R2>>1/gm.  
The following equations show the compensator pole  
zero location and constant gain.  
Vref  
Figure 13 - Type II compensator with  
transconductance amplifier(case 1)  
R3  
Gain=  
... (15)  
... (16)  
... (17)  
R2  
1
F =  
The following parameters are used as an  
example for type II compensator design, three  
1500uF with 19mohm Sanyo electrolytic CAP  
6MV1500WGL are used as output capacitors.  
Coilcraft DO5010P-152HC 1.5uH is used as output  
inductor. The power stage information is that:  
VIN=12V, VOUT=1.2V, IOUT =12A, FS=600kHz.  
1.Calculate the location of LC double pole FLC  
z
2´ p ´ R3 ´ C1  
1
F »  
p
2´ p ´ R3 ´ C2  
and ESR zero FESR  
.
Rev. 1.1  
10/28/07  
14  
NX2142/2142A  
Case 2:  
1
F
=
=
Type II compensator can also be realized by  
simple RC circuit without feedback as shown in figure  
15. R3 and C1 introduce a zero to cancel the double  
pole effect. C2 introduces a pole to suppress the switch-  
ing noise. The following equations show the compen-  
sator pole zero location and constant gain.  
LC  
2´ p ´  
L
OUT ´ COUT  
1
2´ p ´ 1.5uH´ 4500uF  
= 1.94kHz  
1
F
=
ESR  
2´ p ´ ESR´ COUT  
R1  
Gain=gm ´  
´ R3  
... (18)  
... (19)  
... (20)  
1
R1+R2  
=
2´ p ´ 6.33m4500uF  
1
= 5.6kHz  
F =  
z
2´ p ´ R3 ´ C1  
2.Set crossover frequency FO=60kHz>>FESR  
.
1
F »  
p
3. Set R2 equal to 4kW. Based on output  
2´ p ´ R3 ´ C2  
voltage, using equation 21, the final selection of R1 is  
8kW.  
4.Calculate R3 value by the following equation.  
Vout  
VO S C  
Vin  
2 ´ p ´ FO ´ L  
R2  
R 3 =  
´
´ R 2  
Fb  
E S R  
Ve  
R3  
gm  
1
2 ´ p ´ 6 0 k H z ´ 1 . 5 u H  
6 . 3 3 m W  
=
´
´ 4 k W  
R1  
1 0  
Vref  
= 3 6 k W  
C2  
Choose R3 =37.4kW.  
C1  
5. Calculate C1 by setting compensator zero FZ  
at 75% of the LC double pole.  
1
C1=  
Figure 14 - Type II compensator with  
2´ p ´ R3 ´ F  
z
transconductance amplifier(case 2)  
1
=
2´ p ´ 37.4k0.75´ 1.94kHz  
The following is parameters for type II compen-  
sator design. Input voltage is 12V, output voltage is  
2.5V, output inductor is 2.2uH, output capacitors are  
two 680uF with 41mW electrolytic capacitors.  
=2.7nF  
Choose C1=2.7nF.  
F
6. Calculate C2 by setting compensator pole  
at half the swithing frequency.  
p
1.Calculate the location of LC double pole FLC  
1
and ESR zero FESR  
.
C 2  
=
=
p ´ R ´ Fs  
3
1
1
F
=
LC  
2´ p ´  
L
OUT ´ COUT  
p ´ 3 7 . 4k W ´ 6 0 0 k H z  
= 1 4 p F  
Choose C2=15pF.  
1
=
2´ p ´ 2.2uH´ 1360uF  
= 2.9kHz  
Rev. 1.1  
10/28/07  
15  
NX2142/2142A  
Output Voltage Calculation  
1
F
=
=
Output voltage is set by reference voltage and  
external voltage divider. The reference voltage is fixed  
at 0.8V. The divider consists of two ratioed resistors  
ESR  
2´ p ´ ESR´ COUT  
1
2´ p ´ 20.5m1360uF  
so that the output voltage applied at the Fb pin is 0.8V  
when the output voltage is at the desired value. The  
= 5.7kHz  
2.Set R2 equal to10kW. Using equation 18, the  
final selection of R1 is 4.7kW.  
following equation applies to figure 15, which shows  
the relationship between VOUT , VREF and voltage di-  
vider.  
3. Set crossover frequency at 1/10~ 1/5 of the  
swithing frequency, here FO=60kHz.  
4.Calculate R3 value by the following equation.  
Vout  
VOSC 2 ´ p ´ FO ´ L  
VOUT  
1
R2  
R3 =  
=
´
´
´
Fb  
V
RESR  
gm VREF  
in  
1
2´ p ´ 60kHz ´ 2.2uH  
1
´
´
R1  
10  
20.5mW  
2.5V  
2.5mA/V  
Vref  
´
0.8V  
=5kW  
Figure 15 - Voltage divider  
Choose R3 =5kW.  
R 2 ´ VREF  
5. Calculate C1 by setting compensator zero FZ  
at 75% of the LC double pole.  
R1=  
...(21)  
VOUT -VREF  
where R2 is part of the compensator, and the value  
of R1 value can be set by voltage divider.  
1
C1=  
2 ´ p ´ R3 ´ Fz  
1
=
Input Capacitor Selection  
2 ´ p ´ 5k0.75 ´ 2.9kHz  
Input capacitors are usually a mix of high fre-  
quency ceramic capacitors and bulk capacitors. Ce-  
ramic capacitors bypass the high frequency noise, and  
bulk capacitors supply switching current to the  
MOSFETs. Usually 1uF ceramic capacitor is chosen  
to decouple the high frequency noise.The bulk input  
capacitors are decided by voltage rating and RMS cur-  
rent rating. The RMS current in the input capacitors  
=14nF  
Choose C1=15nF.  
F
6. Calculate C2 by setting compensator pole  
at half the swithing frequency.  
p
1
C
=
=
2
p ´ R ´ Fs  
3
1
can be calculated  
as:  
p ´ 5 k W ´ 6 0 0 k H z  
= 5 4 p F  
Choose C2=52pF.  
IRMS = IOUT ´ D ´ 1-D  
VOUT  
D =  
V
INMIN  
...(22)  
VINMIN = 8V, VOUT=1.05V, IOUT=10A, the result of  
input RMS current is 3.4A.  
For higher efficiency, low ESR capacitors are  
recommended. One Sanyo OSCON CAP 25SVP56M  
Rev. 1.1  
10/28/07  
16  
NX2142/2142A  
25V 56uF 28mW with 3.8A RMS rating are chosen  
where QHGATE is the high side MOSFETs gate  
charge,QLGATE is the low side MOSFETs gate  
charge,VHGS  
as input bulk capacitors.  
Power MOSFETs Selection  
is the high side gate source voltage, and VLGS is the  
The NX2142 requires two N-Channel power  
MOSFETs. The selection of MOSFETs is based on  
maximum drain source voltage, gate source voltage,  
maximum current rating, MOSFET on resistance and  
power dissipation. The main consideration is the power  
low side gate source voltage.  
This power dissipation should not exceed maxi-  
mum power dissipation of the driver device.  
Over Current Limit Protection  
Over current Limit for step down converter is  
achieved by sensing current through the low side  
MOSFET. For NX2142, the current limit is decided by  
the RDSON of the low side mosfet. When synchronous  
FET is on, and the voltage on SW pin is below 320mV,  
the over current occurs. The over current limit can be  
calculated by the following equation.  
loss contribution of MOSFETs to the overall converter  
efficiency. In this design example, two STM6912 are  
used. They have the following parameters: VDS=30V, ID  
=6A,RDSON =57mW,QGATE =6.3nC.  
There are two factors causing the MOSFET  
power loss:conduction loss, switching loss.  
Conduction loss is simply defined as:  
HCON =IOUT2 ´ D´ RDS(ON) ´ K  
LCON=IOUT2 ´ (1- D)´ RDS(ON) ´ K  
PTOTAL =P + P  
ISET = 320mV/RDSON  
P
The MOSFET RDSON is calculated in the worst  
case situation, then the current limit for MOSFET  
STM6912 is  
P
...(23)  
HCON  
LCON  
320mV  
320mV  
where the RDS(ON) will increases as MOSFET junc-  
tion temperature increases, K is RDS(ON) temperature  
dependency. As a result, RDS(ON) should be selected  
for the worst case, in which K approximately equals to  
1.4 at 125oC according to datasheet. Conduction loss  
should not exceed package rating or overall system  
thermal budget.  
ISET  
=
=
= 4.6A  
RDSON 1.2´ 57mW  
Layout Considerations  
The layout is very important when designing high  
frequency switching converters. Layout will affect noise  
pickup and can cause a good design to perform with  
less than expected results.  
Switching loss is mainly caused by crossover con-  
duction at the switching transition. The total switching  
loss can be approximated.  
There are two sets of components considered in  
the layout which are power components and small sig-  
nal components. Power components usually consist of  
input capacitors, high-side MOSFET, low-side  
MOSFET, inductor and output capacitors. A noisy en-  
vironment is generated by the power components due  
to the switching power. Small signal components are  
connected to sensitive pins or nodes. A multilayer lay-  
out which includes power plane, ground plane and sig-  
nal plane is recommended .  
1
PSW  
=
´ V ´ IOUT ´ TSW ´ F  
IN S  
...(24)  
2
where IOUT is output current, TSW is the sum of TR  
and TF which can be found in mosfet datasheet, and  
FS is switching frequency. Swithing loss PSW is fre-  
quency dependent.  
Also MOSFET gate driver loss should be consid-  
ered when choosing the proper power MOSFET.  
MOSFET gate driver loss is the loss generated by dis-  
charging the gate capacitor and is dissipated in driver  
circuits.It is proportional to frequency and is defined  
as:  
Layout guidelines:  
1. First put all the power components in the top  
layer connected by wide, copper filled areas. The input  
capacitor, inductor, output capacitor and the MOSFETs  
should be close to each other as possible. This helps  
Pgate = (QHGATE ´ VHGS + QLGATE ´ VLGS )´ FS  
...(25)  
Rev. 1.1  
10/28/07  
17  
NX2142/2142A  
to reduce the EMI radiated by the power loop due to  
the high switching currents through them.  
2. Low ESR capacitor which can handle input  
RMS ripple current and a high frequency decoupling  
ceramic cap which usually is 1uF need to be practi-  
cally touching the drain pin of the upper MOSFET, a  
plane connection is a must.  
3. The output capacitors should be placed as close  
as to the load as possible and plane connection is re-  
quired.  
4. Drain of the low-side MOSFET and source of  
the high-side MOSFET need to be connected thru a  
plane ans as close as possible. A snubber nedds to be  
placed as close to this junction as possible.  
5. Source of the lower MOSFET needs to be con-  
nected to the GND plane with multiple vias. One is not  
enough. This is very important. The same applies to  
the output capacitors and input capacitors.  
6. Hdrv and Ldrv pins should be as close to  
MOSFET gate as possible. The gate traces should be  
wide and short. A place for gate drv resistors is needed  
to fine tune noise if needed.  
7. Vcc capacitor, BST capacitor or any other by-  
passing capacitor needs to be placed first around the  
IC and as close as possible. The capacitor on comp to  
GND or comp back to FB needs to be place as close to  
the pin as well as resistor divider.  
8. The output sense line which is sensing output  
back to the resistor divider should not go through high  
frequency signals.  
9. All GNDs need to go directly thru via to GND  
plane.  
10. The feedback part of the system should be  
kept away from the inductor and other noise sources,  
and be placed close to the IC.  
11. In multilayer PCB, separate power ground and  
analog ground. These two grounds must be connected  
together on the PC board layout at a single point. The  
goal is to localize the high current path to a separate  
loop that does not interfere with the more sensitive ana-  
log control function.  
Rev. 1.1  
10/28/07  
18  
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